Base | Representation |
---|---|
bin | 110001001111011100000101… |
… | …1101001110101010100000000 |
3 | 2002210120212102222202012220010 |
4 | 1202132320023221311110000 |
5 | 423232402144131314224 |
6 | 4133105220111544520 |
7 | 160142433520522431 |
oct | 14236701351652400 |
9 | 2083525388665803 |
10 | 433130467448064 |
11 | 116010666206171 |
12 | 406b370522b140 |
13 | 1578b04918a0b9 |
14 | 78d58ab0b7488 |
15 | 3511ab6547e29 |
hex | 189ee0ba75500 |
433130467448064 has 72 divisors (see below), whose sum is σ = 1154620985187040. Its totient is φ = 144143580284928.
The previous prime is 433130467448011. The next prime is 433130467448069. The reversal of 433130467448064 is 460844764031334.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 433130467447995 and 433130467448013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (433130467448069) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 455075467 + ... + 456026250.
Almost surely, 2433130467448064 is an apocalyptic number.
It is an amenable number.
433130467448064 is an abundant number, since it is smaller than the sum of its proper divisors (721490517738976).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
433130467448064 is an equidigital number, since it uses as much as digits as its factorization.
433130467448064 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 911102355 (or 911102341 counting only the distinct ones).
The product of its (nonzero) digits is 55738368, while the sum is 57.
The spelling of 433130467448064 in words is "four hundred thirty-three trillion, one hundred thirty billion, four hundred sixty-seven million, four hundred forty-eight thousand, sixty-four".
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