Base | Representation |
---|---|
bin | 11001110100101… |
… | …101111100000111 |
3 | 1010012020101100100 |
4 | 121310231330013 |
5 | 1341403000210 |
6 | 110554015143 |
7 | 13510364460 |
oct | 3164557407 |
9 | 1105211310 |
10 | 433250055 |
11 | 2026161a7 |
12 | 1011174b3 |
13 | 6b9b39a4 |
14 | 4177bd67 |
15 | 280805c0 |
hex | 19d2df07 |
433250055 has 48 divisors (see below), whose sum is σ = 861606720. Its totient is φ = 197282304.
The previous prime is 433250047. The next prime is 433250071. The reversal of 433250055 is 550052334.
It is not a de Polignac number, because 433250055 - 23 = 433250047 is a prime.
It is a super-2 number, since 2×4332500552 = 375411220315006050, which contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 82179 + ... + 87291.
It is an arithmetic number, because the mean of its divisors is an integer number (17950140).
Almost surely, 2433250055 is an apocalyptic number.
433250055 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
433250055 is a deficient number, since it is larger than the sum of its proper divisors (428356665).
433250055 is a wasteful number, since it uses less digits than its factorization.
433250055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5400 (or 5397 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 27.
The square root of 433250055 is about 20814.6596176829. The cubic root of 433250055 is about 756.6810808211.
The spelling of 433250055 in words is "four hundred thirty-three million, two hundred fifty thousand, fifty-five".
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