Base | Representation |
---|---|
bin | 111111001010001110110… |
… | …001001110111111111001 |
3 | 120100221002211012201002200 |
4 | 333022032301032333321 |
5 | 1032102424413140441 |
6 | 13121524550220413 |
7 | 625401661215354 |
oct | 77121661167771 |
9 | 16327084181080 |
10 | 4340312240121 |
11 | 14237971205a0 |
12 | 5a1221954709 |
13 | 25639c5a1a60 |
14 | 1101022cb29b |
15 | 77d7c77b7b6 |
hex | 3f28ec4eff9 |
4340312240121 has 96 divisors (see below), whose sum is σ = 7804419517440. Its totient is φ = 2283619737600.
The previous prime is 4340312240107. The next prime is 4340312240123. The reversal of 4340312240121 is 1210422130434.
4340312240121 is a `hidden beast` number, since 4 + 3 + 403 + 1 + 2 + 240 + 12 + 1 = 666.
It is not a de Polignac number, because 4340312240121 - 218 = 4340311977977 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4340312240123) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 29704440 + ... + 29850198.
It is an arithmetic number, because the mean of its divisors is an integer number (81296036640).
Almost surely, 24340312240121 is an apocalyptic number.
It is an amenable number.
4340312240121 is a deficient number, since it is larger than the sum of its proper divisors (3464107277319).
4340312240121 is a wasteful number, since it uses less digits than its factorization.
4340312240121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147167 (or 147164 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 4340312240121 its reverse (1210422130434), we get a palindrome (5550734370555).
The spelling of 4340312240121 in words is "four trillion, three hundred forty billion, three hundred twelve million, two hundred forty thousand, one hundred twenty-one".
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