Base | Representation |
---|---|
bin | 101000011011100111… |
… | …110110011001001000 |
3 | 11011001112102012021011 |
4 | 220123213312121020 |
5 | 1202402223313300 |
6 | 31535501253304 |
7 | 3064550203624 |
oct | 503347663110 |
9 | 134045365234 |
10 | 43413104200 |
11 | 17458624814 |
12 | 84b6b64234 |
13 | 412b215b4b |
14 | 215b9ca184 |
15 | 11e147beba |
hex | a1b9f6648 |
43413104200 has 48 divisors (see below), whose sum is σ = 103397327460. Its totient is φ = 16941696000.
The previous prime is 43413104183. The next prime is 43413104209. The reversal of 43413104200 is 240131434.
43413104200 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 6 ways, for example, as 4905321444 + 38507782756 = 70038^2 + 196234^2 .
It is not an unprimeable number, because it can be changed into a prime (43413104209) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2638941 + ... + 2655340.
Almost surely, 243413104200 is an apocalyptic number.
43413104200 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
43413104200 is an abundant number, since it is smaller than the sum of its proper divisors (59984223260).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43413104200 is a wasteful number, since it uses less digits than its factorization.
43413104200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5294338 (or 5294329 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 43413104200 its reverse (240131434), we get a palindrome (43653235634).
The spelling of 43413104200 in words is "forty-three billion, four hundred thirteen million, one hundred four thousand, two hundred".
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