48340013340 has 96 divisors (see below), whose sum is σ = 137803680000. Its totient is φ = 12657682432.

The previous prime is 48340013333. The next prime is 48340013347. The reversal of 48340013340 is 4331004384.

It is an interprime number because it is at equal distance from previous prime (48340013333) and next prime (48340013347).

It is a super-2 number, since 2×48340013340² (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 48340013298 and 48340013307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (48340013347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3281311 + ... + 3296009.

It is an arithmetic number, because the mean of its divisors is an integer number (1435455000).

Almost surely, 2^48340013340 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 48340013340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (68901840000).

48340013340 is an abundant number, since it is smaller than the sum of its proper divisors (89463666660).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

48340013340 is a wasteful number, since it uses less digits than its factorization.

48340013340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15699 (or 15697 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 30.

The spelling of 48340013340 in words is "forty-eight billion, three hundred forty million, thirteen thousand, three hundred forty".