Base | Representation |
---|---|
bin | 10110010110011100011110… |
… | …01001011100001100000101 |
3 | 20110000122222221222222121120 |
4 | 23023032033021130030011 |
5 | 22420232102332303043 |
6 | 252311022142504153 |
7 | 13231643456065020 |
oct | 1313161711341405 |
9 | 213018887888546 |
10 | 49149712384773 |
11 | 1472a304346810 |
12 | 5619663295059 |
13 | 2156a4b253c80 |
14 | c1cc046841b7 |
15 | 5a376bb13983 |
hex | 2cb38f25c305 |
49149712384773 has 64 divisors (see below), whose sum is σ = 87997248847872. Its totient is φ = 23565895649280.
The previous prime is 49149712384753. The next prime is 49149712384781. The reversal of 49149712384773 is 37748321794194.
It is not a de Polignac number, because 49149712384773 - 214 = 49149712368389 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49149712384698 and 49149712384707.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49149712384753) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 28862965 + ... + 30518357.
It is an arithmetic number, because the mean of its divisors is an integer number (1374957013248).
Almost surely, 249149712384773 is an apocalyptic number.
It is an amenable number.
49149712384773 is a deficient number, since it is larger than the sum of its proper divisors (38847536463099).
49149712384773 is a wasteful number, since it uses less digits than its factorization.
49149712384773 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1665314.
The product of its digits is 256048128, while the sum is 69.
The spelling of 49149712384773 in words is "forty-nine trillion, one hundred forty-nine billion, seven hundred twelve million, three hundred eighty-four thousand, seven hundred seventy-three".
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