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49488742626311 is a prime number
BaseRepresentation
bin10110100000010011111101…
…11011001011010000000111
320111020002002120012201100002
423100021332323023100013
522441310421103020221
6253130451533311515
713265305114433132
oct1320117673132007
9214202076181302
1049488742626311
111485007005317a
1256732bb93559b
13217c9cb255b51
14c313a7279219
155ac4b0a9d80b
hex2d027eecb407

49488742626311 has 2 divisors, whose sum is σ = 49488742626312. Its totient is φ = 49488742626310.

The previous prime is 49488742626187. The next prime is 49488742626313. The reversal of 49488742626311 is 11362624788494.

It is a happy number.

49488742626311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 49488742626311 - 226 = 49488675517447 is a prime.

Together with 49488742626313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49488742626313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24744371313155 + 24744371313156.

It is an arithmetic number, because the mean of its divisors is an integer number (24744371313156).

Almost surely, 249488742626311 is an apocalyptic number.

49488742626311 is a deficient number, since it is larger than the sum of its proper divisors (1).

49488742626311 is an equidigital number, since it uses as much as digits as its factorization.

49488742626311 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 111476736, while the sum is 65.

The spelling of 49488742626311 in words is "forty-nine trillion, four hundred eighty-eight billion, seven hundred forty-two million, six hundred twenty-six thousand, three hundred eleven".