| Base | Representation |
|---|---|
| bin | 10110100011001000000000… |
| … | …01110110111111000000000 |
| 3 | 20111120022120212121200101000 |
| 4 | 23101210000032313320000 |
| 5 | 22444401400220044300 |
| 6 | 253243115141012000 |
| 7 | 13305266320035360 |
| oct | 1321440016677000 |
| 9 | 214508525550330 |
| 10 | 49585401331200 |
| 11 | 148880613a9859 |
| 12 | 5689b966b4000 |
| 13 | 2188b63755097 |
| 14 | c35d366509a0 |
| 15 | 5aec6b7c9c00 |
| hex | 2d19003b7e00 |
49585401331200 has 7680 divisors, whose sum is σ = 252518694912000. Its totient is φ = 9249384038400.
The previous prime is 49585401331187. The next prime is 49585401331201. The reversal of 49585401331200 is 213310458594.
49585401331200 is a `hidden beast` number, since 4 + 9 + 5 + 8 + 5 + 401 + 3 + 31 + 200 = 666.
It is a tau number, because it is divible by the number of its divisors (7680).
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49585401331201) by changing a digit.
It is a polite number, since it can be written in 767 ways as a sum of consecutive naturals, for example, 557139340756 + ... + 557139340844.
It is an arithmetic number, because the mean of its divisors is an integer number (32880038400).
Almost surely, 249585401331200 is an apocalyptic number.
49585401331200 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 49585401331200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (126259347456000).
49585401331200 is an abundant number, since it is smaller than the sum of its proper divisors (202933293580800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
49585401331200 is a wasteful number, since it uses less digits than its factorization.
49585401331200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 223 (or 196 counting only the distinct ones).
The product of its (nonzero) digits is 518400, while the sum is 45.
Adding to 49585401331200 its reverse (213310458594), we get a palindrome (49798711789794).
The spelling of 49585401331200 in words is "forty-nine trillion, five hundred eighty-five billion, four hundred one million, three hundred thirty-one thousand, two hundred".
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