Base | Representation |
---|---|
bin | 10111001111001101111010… |
… | …01100101001001011011110 |
3 | 20200221011001202010200022100 |
4 | 23213212331030221023132 |
5 | 23144212104413104414 |
6 | 300403111051025530 |
7 | 13522611360244545 |
oct | 1347467514511336 |
9 | 220834052120270 |
10 | 51100400128734 |
11 | 15311615762790 |
12 | 589372473b2a6 |
13 | 22689933862c8 |
14 | c893b5cab15c |
15 | 5d938a7ec609 |
hex | 2e79bd3292de |
51100400128734 has 48 divisors (see below), whose sum is σ = 120784117250160. Its totient is φ = 15484796234880.
The previous prime is 51100400128709. The next prime is 51100400128741. The reversal of 51100400128734 is 43782100400115.
51100400128734 is a `hidden beast` number, since 51 + 10 + 0 + 400 + 128 + 73 + 4 = 666.
It is a super-2 number, since 2×511004001287342 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16853674 + ... + 19653170.
It is an arithmetic number, because the mean of its divisors is an integer number (2516335776045).
Almost surely, 251100400128734 is an apocalyptic number.
51100400128734 is an abundant number, since it is smaller than the sum of its proper divisors (69683717121426).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51100400128734 is a wasteful number, since it uses less digits than its factorization.
51100400128734 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2891705 (or 2891702 counting only the distinct ones).
The product of its (nonzero) digits is 26880, while the sum is 36.
Adding to 51100400128734 its reverse (43782100400115), we get a palindrome (94882500528849).
The spelling of 51100400128734 in words is "fifty-one trillion, one hundred billion, four hundred million, one hundred twenty-eight thousand, seven hundred thirty-four".
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