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51101136407 is a prime number
BaseRepresentation
bin101111100101110111…
…010111011000010111
311212220022210200210202
4233211313113120113
51314123342331112
635250414411115
73456222330656
oct574567273027
9155808720722
1051101136407
111a743294142
129aa1800a9b
134a84c2aa29
14268aa8719d
1514e13a26c2
hexbe5dd7617

51101136407 has 2 divisors, whose sum is σ = 51101136408. Its totient is φ = 51101136406.

The previous prime is 51101136353. The next prime is 51101136461. The reversal of 51101136407 is 70463110115.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (51101136353) and next prime (51101136461).

It is a cyclic number.

It is not a de Polignac number, because 51101136407 - 210 = 51101135383 is a prime.

It is a super-2 number, since 2×511011364072 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 51101136407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51101136607) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550568203 + 25550568204.

It is an arithmetic number, because the mean of its divisors is an integer number (25550568204).

Almost surely, 251101136407 is an apocalyptic number.

51101136407 is a deficient number, since it is larger than the sum of its proper divisors (1).

51101136407 is an equidigital number, since it uses as much as digits as its factorization.

51101136407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 29.

The spelling of 51101136407 in words is "fifty-one billion, one hundred one million, one hundred thirty-six thousand, four hundred seven".