Base | Representation |
---|---|
bin | 101111100110011001… |
… | …011000111001101111 |
3 | 11212220221120211112211 |
4 | 233212121120321233 |
5 | 1314133133234120 |
6 | 35251333511251 |
7 | 3456361206160 |
oct | 574631307157 |
9 | 155827524484 |
10 | 51110055535 |
11 | 1a748326220 |
12 | 9aa47a2527 |
13 | 4a86a31616 |
14 | 268bd29767 |
15 | 14e206525a |
hex | be6658e6f |
51110055535 has 64 divisors (see below), whose sum is σ = 81481282560. Its totient is φ = 29795051520.
The previous prime is 51110055517. The next prime is 51110055541. The reversal of 51110055535 is 53555001115.
It is not a de Polignac number, because 51110055535 - 215 = 51110022767 is a prime.
It is a super-2 number, since 2×511100555352 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51110055497 and 51110055506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1002696 + ... + 1052434.
It is an arithmetic number, because the mean of its divisors is an integer number (1273145040).
Almost surely, 251110055535 is an apocalyptic number.
51110055535 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
51110055535 is a deficient number, since it is larger than the sum of its proper divisors (30371227025).
51110055535 is a wasteful number, since it uses less digits than its factorization.
51110055535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49936.
The product of its (nonzero) digits is 9375, while the sum is 31.
The spelling of 51110055535 in words is "fifty-one billion, one hundred ten million, fifty-five thousand, five hundred thirty-five".
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