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51121300 = 2252511213
BaseRepresentation
bin1100001100000…
…0110010010100
310120012020020111
43003000302110
5101041340200
65023412404
71160344456
oct303006224
9116166214
1051121300
112694720a
1215154104
13a78b8b9
146b0a2d6
15474c0ba
hex30c0c94

51121300 has 18 divisors (see below), whose sum is σ = 110933438. Its totient is φ = 20448480.

The previous prime is 51121253. The next prime is 51121307. The reversal of 51121300 is 312115.

It can be written as a sum of positive squares in 3 ways, for example, as 5071504 + 46049796 = 2252^2 + 6786^2 .

It is a super-2 number, since 2×511213002 = 5226774627380000, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51121307) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 255507 + ... + 255706.

Almost surely, 251121300 is an apocalyptic number.

51121300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

51121300 is an abundant number, since it is smaller than the sum of its proper divisors (59812138).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51121300 is a wasteful number, since it uses less digits than its factorization.

51121300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 511227 (or 511220 counting only the distinct ones).

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 51121300 is about 7149.9160834236. The cubic root of 51121300 is about 371.1367523316.

Adding to 51121300 its reverse (312115), we get a palindrome (51433415).

The spelling of 51121300 in words is "fifty-one million, one hundred twenty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 511213 1022426 2044852 2556065 5112130 10224260 12780325 25560650 51121300