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511225130000 = 24541317772213
BaseRepresentation
bin1110111000001110110…
…01000110110000010000
31210212120011021101210002
413130013121012300100
531333442113130000
61030504212425132
751635430623024
oct7340731066020
91725504241702
10511225130000
1118789a292842
12830b43181a8
13392928bab30
141aa59d78384
15d4713428d5
hex7707646c10

511225130000 has 200 divisors, whose sum is σ = 1334289709368. Its totient is φ = 188568576000.

The previous prime is 511225129927. The next prime is 511225130089. The reversal of 511225130000 is 31522115.

It is a happy number.

It can be written as a sum of positive squares in 20 ways, for example, as 475597812496 + 35627317504 = 689636^2 + 188752^2 .

It is a tau number, because it is divible by the number of its divisors (200).

It is a super-2 number, since 2×5112251300002 (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 231008894 + ... + 231011106.

Almost surely, 2511225130000 is an apocalyptic number.

511225130000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 511225130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (667144854684).

511225130000 is an abundant number, since it is smaller than the sum of its proper divisors (823064579368).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

511225130000 is a wasteful number, since it uses less digits than its factorization.

511225130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4031 (or 4010 counting only the distinct ones).

The product of its (nonzero) digits is 300, while the sum is 20.

Adding to 511225130000 its reverse (31522115), we get a palindrome (511256652115).

The spelling of 511225130000 in words is "five hundred eleven billion, two hundred twenty-five million, one hundred thirty thousand".