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5112303011544 = 233213012625481
BaseRepresentation
bin100101001100100110100…
…0000010100011011011000
3200002201202012001012201010
41022121031000110123120
51132224444032332134
614512320511453520
71035231430416021
oct112311500243330
920081665035633
105112303011544
1116a112a8552a3
126a696bb272a0
132b111b74bca1
1413961877dc48
158ceb1ad2ce9
hex4a64d0146d8

5112303011544 has 16 divisors (see below), whose sum is σ = 12780757528920. Its totient is φ = 1704101003840.

The previous prime is 5112303011513. The next prime is 5112303011567. The reversal of 5112303011544 is 4451103032115.

It is a super-2 number, since 2×51123030115442 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106506312717 + ... + 106506312764.

Almost surely, 25112303011544 is an apocalyptic number.

It is an amenable number.

5112303011544 is an abundant number, since it is smaller than the sum of its proper divisors (7668454517376).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5112303011544 is a wasteful number, since it uses less digits than its factorization.

5112303011544 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213012625490 (or 213012625486 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 5112303011544 its reverse (4451103032115), we get a palindrome (9563406043659).

The spelling of 5112303011544 in words is "five trillion, one hundred twelve billion, three hundred three million, eleven thousand, five hundred forty-four".

Divisors: 1 2 3 4 6 8 12 24 213012625481 426025250962 639037876443 852050501924 1278075752886 1704101003848 2556151505772 5112303011544