Base | Representation |
---|---|
bin | 10111001111111010011101… |
… | …00100111000001011000000 |
3 | 20201000102210100022221100110 |
4 | 23213331032210320023000 |
5 | 23200110043341430100 |
6 | 300422104032351320 |
7 | 13524416106025044 |
oct | 1347751644701300 |
9 | 221012710287313 |
10 | 51124314014400 |
11 | 153207774a8a60 |
12 | 58982993a5540 |
13 | 226b004891203 |
14 | c8a603ccc024 |
15 | 5d9cd9e7d250 |
hex | 2e7f4e9382c0 |
51124314014400 has 336 divisors, whose sum is σ = 183039312912768. Its totient is φ = 12389658624000.
The previous prime is 51124314014393. The next prime is 51124314014419. The reversal of 51124314014400 is 441041342115.
51124314014400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×511243140144002 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 160405599 + ... + 160724001.
Almost surely, 251124314014400 is an apocalyptic number.
51124314014400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 51124314014400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (91519656456384).
51124314014400 is an abundant number, since it is smaller than the sum of its proper divisors (131914998898368).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51124314014400 is a wasteful number, since it uses less digits than its factorization.
51124314014400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 321480 (or 321465 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 30.
Adding to 51124314014400 its reverse (441041342115), we get a palindrome (51565355356515).
The spelling of 51124314014400 in words is "fifty-one trillion, one hundred twenty-four billion, three hundred fourteen million, fourteen thousand, four hundred".
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