Base | Representation |
---|---|
bin | 111010000111110111110011… |
… | …1111100110010100101110100 |
3 | 2111001012112100112112122111002 |
4 | 1310033233213330302211310 |
5 | 1014002401400312131431 |
6 | 5011203241523102432 |
7 | 212454656343550133 |
oct | 16417574774624564 |
9 | 2431175315478432 |
10 | 511255323552116 |
11 | 1389a118a823480 |
12 | 49410859511a18 |
13 | 18c37229a5b460 |
14 | 9036c6544991a |
15 | 3e18dce43a3cb |
hex | 1d0fbe7f32974 |
511255323552116 has 96 divisors (see below), whose sum is σ = 1062818116018176. Its totient is φ = 212136531120000.
The previous prime is 511255323552053. The next prime is 511255323552131. The reversal of 511255323552116 is 611255323552115.
It is a super-2 number, since 2×5112553235521162 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5989151 + ... + 32532761.
It is an arithmetic number, because the mean of its divisors is an integer number (11071022041856).
Almost surely, 2511255323552116 is an apocalyptic number.
It is an amenable number.
511255323552116 is an abundant number, since it is smaller than the sum of its proper divisors (551562792466060).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
511255323552116 is a wasteful number, since it uses less digits than its factorization.
511255323552116 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26544013 (or 26544011 counting only the distinct ones).
The product of its digits is 1350000, while the sum is 47.
Subtracting 511255323552116 from its reverse (611255323552115), we obtain a palindrome (99999999999999).
The spelling of 511255323552116 in words is "five hundred eleven trillion, two hundred fifty-five billion, three hundred twenty-three million, five hundred fifty-two thousand, one hundred sixteen".
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