5113125 has 50 divisors (see below), whose sum is σ = 9639102. Its totient is φ = 2700000.

The previous prime is 5113123. The next prime is 5113127. The reversal of 5113125 is 5213115.

Added to its reverse (5213115) it gives a triangular number (10326240 = T₄₅₄₄).

It is an interprime number because it is at equal distance from previous prime (5113123) and next prime (5113127).

It can be written as a sum of positive squares in 5 ways, for example, as 715716 + 4397409 = 846^2 + 2097^2 .

It is not a de Polignac number, because 5113125 - 2¹ = 5113123 is a prime.

It is a super-3 number, since 3×5113125³ (a number of 21 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 5113098 and 5113107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5113123) by changing a digit.

It is a polite number, since it can be written in 49 ways as a sum of consecutive naturals, for example, 50575 + ... + 50675.

Almost surely, 2^5113125 is an apocalyptic number.

It is an amenable number.

5113125 is a deficient number, since it is larger than the sum of its proper divisors (4525977).

5113125 is an equidigital number, since it uses as much as digits as its factorization.

5113125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 133 (or 109 counting only the distinct ones).

The product of its digits is 150, while the sum is 18.

The square root of 5113125 is about 2261.2220147522. Note that the first 3 decimals coincide. The cubic root of 5113125 is about 172.2775961763.

Adding to 5113125 its reverse (5213115), we get a triangular number (10326240 = T₄₅₄₄).

The spelling of 5113125 in words is "five million, one hundred thirteen thousand, one hundred twenty-five".