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5113319 is a prime number
BaseRepresentation
bin10011100000010111100111
3100121210011012
4103200113213
52302111234
6301332435
761314431
oct23402747
910553135
105113319
112982792
12186711b
1310a0543
14971651
156b00ce
hex4e05e7

5113319 has 2 divisors, whose sum is σ = 5113320. Its totient is φ = 5113318.

The previous prime is 5113307. The next prime is 5113321. The reversal of 5113319 is 9133115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5113319 - 28 = 5113063 is a prime.

It is a super-2 number, since 2×51133192 = 52292062391522, which contains 22 as substring.

Together with 5113321, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5113294 and 5113303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5113369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556659 + 2556660.

It is an arithmetic number, because the mean of its divisors is an integer number (2556660).

Almost surely, 25113319 is an apocalyptic number.

5113319 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113319 is an equidigital number, since it uses as much as digits as its factorization.

5113319 is an evil number, because the sum of its binary digits is even.

The product of its digits is 405, while the sum is 23.

The square root of 5113319 is about 2261.2649115042. The cubic root of 5113319 is about 172.2797749763.

The spelling of 5113319 in words is "five million, one hundred thirteen thousand, three hundred nineteen".