Base | Representation |
---|---|
bin | 1001100001101010… |
… | …01001101101001111 |
3 | 111012102021122012010 |
4 | 10300311021231033 |
5 | 40433214111210 |
6 | 2203251112303 |
7 | 240510020436 |
oct | 46065115517 |
9 | 14172248163 |
10 | 5114207055 |
11 | 2194922501 |
12 | ba88a2693 |
13 | 636707b29 |
14 | 36731011d |
15 | 1edeb5920 |
hex | 130d49b4f |
5114207055 has 8 divisors (see below), whose sum is σ = 8182731312. Its totient is φ = 2727577088.
The previous prime is 5114207041. The next prime is 5114207057. The reversal of 5114207055 is 5507024115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5114207055 - 24 = 5114207039 is a prime.
It is a super-2 number, since 2×51142070552 = 52310227602823546050, which contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5114207057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 170473554 + ... + 170473583.
It is an arithmetic number, because the mean of its divisors is an integer number (1022841414).
Almost surely, 25114207055 is an apocalyptic number.
5114207055 is a deficient number, since it is larger than the sum of its proper divisors (3068524257).
5114207055 is a wasteful number, since it uses less digits than its factorization.
5114207055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 340947145.
The product of its (nonzero) digits is 7000, while the sum is 30.
The square root of 5114207055 is about 71513.6843897726. The cubic root of 5114207055 is about 1722.8974795468.
The spelling of 5114207055 in words is "five billion, one hundred fourteen million, two hundred seven thousand, fifty-five".
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