Base | Representation |
---|---|
bin | 100101010000110001111… |
… | …0101001001100100110110 |
3 | 200010120220112002212112120 |
4 | 1022201203311021210312 |
5 | 1132401333112102240 |
6 | 14520403123500410 |
7 | 1035666663565260 |
oct | 112414365114466 |
9 | 20116815085476 |
10 | 5121275894070 |
11 | 16a4a14804796 |
12 | 6a8654b27706 |
13 | 2b1c1b6c632b |
14 | 139c2a336b30 |
15 | 8d339704ad0 |
hex | 4a863d49936 |
5121275894070 has 128 divisors (see below), whose sum is σ = 14792788684800. Its totient is φ = 1108476876672.
The previous prime is 5121275894069. The next prime is 5121275894101. The reversal of 5121275894070 is 704985721215.
It is a happy number.
It is a super-2 number, since 2×51212758940702 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8762241 + ... + 9328419.
It is an arithmetic number, because the mean of its divisors is an integer number (115568661600).
Almost surely, 25121275894070 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 5121275894070, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (7396394342400).
5121275894070 is an abundant number, since it is smaller than the sum of its proper divisors (9671512790730).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5121275894070 is a wasteful number, since it uses less digits than its factorization.
5121275894070 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 568482.
The product of its (nonzero) digits is 1411200, while the sum is 51.
The spelling of 5121275894070 in words is "five trillion, one hundred twenty-one billion, two hundred seventy-five million, eight hundred ninety-four thousand, seventy".
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