Base | Representation |
---|---|
bin | 100101010001101011011… |
… | …0000101110101010010111 |
3 | 200010202212220101122112002 |
4 | 1022203112300232222113 |
5 | 1132414310223140340 |
6 | 14521322324145515 |
7 | 1036065526314023 |
oct | 112432660565227 |
9 | 20122786348462 |
10 | 5123204115095 |
11 | 16a5814185790 |
12 | 6a8ab283829b |
13 | 2b216802b211 |
14 | 139d70469383 |
15 | 8d3edb39715 |
hex | 4a8d6c2ea97 |
5123204115095 has 8 divisors (see below), whose sum is σ = 6706739932560. Its totient is φ = 3725966629120.
The previous prime is 5123204115067. The next prime is 5123204115101. The reversal of 5123204115095 is 5905114023215.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5123204115095 - 216 = 5123204049559 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46574582810 + ... + 46574582919.
It is an arithmetic number, because the mean of its divisors is an integer number (838342491570).
Almost surely, 25123204115095 is an apocalyptic number.
5123204115095 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5123204115095 is a deficient number, since it is larger than the sum of its proper divisors (1583535817465).
5123204115095 is a wasteful number, since it uses less digits than its factorization.
5123204115095 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93149165745.
The product of its (nonzero) digits is 54000, while the sum is 38.
The spelling of 5123204115095 in words is "five trillion, one hundred twenty-three billion, two hundred four million, one hundred fifteen thousand, ninety-five".
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