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52111322311125 = 3537111804721119
BaseRepresentation
bin10111101100101000111001…
…10110101110100111010101
320211111210102122120110100010
423312110130312232213111
523312242442002424000
6302455335545510433
713655630101103130
oct1366243466564725
9224453378513303
1052111322311125
11156713189a59a0
125a176344a2419
1323100cc40155c
14cc22b6b29217
15605805d80d50
hex2f651cdae9d5

52111322311125 has 64 divisors (see below), whose sum is σ = 108110013972480. Its totient is φ = 21656653416000.

The previous prime is 52111322311121. The next prime is 52111322311151.

52111322311125 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 52111322311125 - 22 = 52111322311121 is a prime.

It is a super-2 number, since 2×521113223111252 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 52111322311092 and 52111322311101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52111322311121) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 902331685 + ... + 902389434.

It is an arithmetic number, because the mean of its divisors is an integer number (1689218968320).

Almost surely, 252111322311125 is an apocalyptic number.

52111322311125 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

It is an amenable number.

52111322311125 is an abundant number, since it is smaller than the sum of its proper divisors (55998691661355).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

52111322311125 is a wasteful number, since it uses less digits than its factorization.

52111322311125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1804721155 (or 1804721145 counting only the distinct ones).

The product of its digits is 3600, while the sum is 30.

It can be divided in two parts, 5211132 and 2311125, that added together give a palindrome (7522257).

The spelling of 52111322311125 in words is "fifty-two trillion, one hundred eleven billion, three hundred twenty-two million, three hundred eleven thousand, one hundred twenty-five".

Divisors: 1 3 5 7 11 15 21 25 33 35 55 75 77 105 125 165 175 231 275 375 385 525 825 875 1155 1375 1925 2625 4125 5775 9625 28875 1804721119 5414163357 9023605595 12633047833 19851932309 27070816785 37899143499 45118027975 59555796927 63165239165 99259661545 135354083925 138963526163 189495717495 225590139875 297778984635 315826195825 416890578489 496298307725 676770419625 694817630815 947478587475 1488894923175 1579130979125 2084452892445 2481491538625 3474088154075 4737392937375 7444474615875 10422264462225 17370440770375 52111322311125