Base | Representation |
---|---|
bin | 10111111001001001100100… |
… | …11111110110001011001111 |
3 | 20220000212222022200100121221 |
4 | 23330210302133312023033 |
5 | 23341313320112004020 |
6 | 303425030313504211 |
7 | 14031655321264132 |
oct | 1374446237661317 |
9 | 226025868610557 |
10 | 52541182141135 |
11 | 15817654633556 |
12 | 5a869bb712067 |
13 | 23417c606815c |
14 | cd901488a219 |
15 | 611ab3e166aa |
hex | 2fc9327f62cf |
52541182141135 has 8 divisors (see below), whose sum is σ = 63208233228096. Its totient is φ = 41927069273760.
The previous prime is 52541182141079. The next prime is 52541182141229. The reversal of 52541182141135 is 53114128114525.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 52541182141135 - 221 = 52541180043983 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 52541182141091 and 52541182141100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13234552711 + ... + 13234556680.
It is an arithmetic number, because the mean of its divisors is an integer number (7901029153512).
Almost surely, 252541182141135 is an apocalyptic number.
52541182141135 is a deficient number, since it is larger than the sum of its proper divisors (10667051086961).
52541182141135 is a wasteful number, since it uses less digits than its factorization.
52541182141135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26469109793.
The product of its digits is 192000, while the sum is 43.
The spelling of 52541182141135 in words is "fifty-two trillion, five hundred forty-one billion, one hundred eighty-two million, one hundred forty-one thousand, one hundred thirty-five".
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