Base | Representation |
---|---|
bin | 1100101000111… |
… | …0101001101100 |
3 | 10200202100022011 |
4 | 3022032221230 |
5 | 102032404400 |
6 | 5132131004 |
7 | 1212414100 |
oct | 312165154 |
9 | 120670264 |
10 | 53013100 |
11 | 27a19588 |
12 | 15906a64 |
13 | aca19ca |
14 | 707d900 |
15 | 49c28ba |
hex | 328ea6c |
53013100 has 108 divisors (see below), whose sum is σ = 138532800. Its totient is φ = 17539200.
The previous prime is 53013083. The next prime is 53013101. The reversal of 53013100 is 131035.
53013100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×530131002 = 5620777543220000, which contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53013101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 151726 + ... + 152074.
Almost surely, 253013100 is an apocalyptic number.
53013100 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53013100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (69266400).
53013100 is an abundant number, since it is smaller than the sum of its proper divisors (85519700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53013100 is a wasteful number, since it uses less digits than its factorization.
53013100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 408 (or 394 counting only the distinct ones).
The product of its (nonzero) digits is 45, while the sum is 13.
The square root of 53013100 is about 7281.0095453859. The cubic root of 53013100 is about 375.6595208874.
Adding to 53013100 its reverse (131035), we get a palindrome (53144135).
The spelling of 53013100 in words is "fifty-three million, thirteen thousand, one hundred".
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