Base | Representation |
---|---|
bin | 110001010111110101… |
… | …010100010111100000 |
3 | 12001211120200201020202 |
4 | 301113311110113200 |
5 | 1332032334434100 |
6 | 40204240524332 |
7 | 3554500533254 |
oct | 612765242740 |
9 | 161746621222 |
10 | 53013202400 |
11 | 20534630674 |
12 | a3360206a8 |
13 | 4ccb0c7622 |
14 | 27cc9b2264 |
15 | 15a41957d5 |
hex | c57d545e0 |
53013202400 has 36 divisors (see below), whose sum is σ = 129418482312. Its totient is φ = 21205280640.
The previous prime is 53013202397. The next prime is 53013202421. The reversal of 53013202400 is 420231035.
It is a happy number.
53013202400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 33132452 + ... + 33134051.
It is an arithmetic number, because the mean of its divisors is an integer number (3594957842).
Almost surely, 253013202400 is an apocalyptic number.
53013202400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53013202400 is an abundant number, since it is smaller than the sum of its proper divisors (76405279912).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53013202400 is a wasteful number, since it uses less digits than its factorization.
53013202400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66266523 (or 66266510 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 20.
Adding to 53013202400 its reverse (420231035), we get a palindrome (53433433435).
The spelling of 53013202400 in words is "fifty-three billion, thirteen million, two hundred two thousand, four hundred".
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