Base | Representation |
---|---|
bin | 110001010111111010… |
… | …011001010000010111 |
3 | 12001211200012022200112 |
4 | 301113322121100113 |
5 | 1332033210030033 |
6 | 40204325233235 |
7 | 3554515045055 |
oct | 612772312027 |
9 | 161750168615 |
10 | 53014533143 |
11 | 2053535a460 |
12 | a33656281b |
13 | 4ccb472250 |
14 | 27ccc3b1d5 |
15 | 15a4359c48 |
hex | c57e99417 |
53014533143 has 8 divisors (see below), whose sum is σ = 62282808336. Its totient is φ = 44487720000.
The previous prime is 53014533119. The next prime is 53014533149. The reversal of 53014533143 is 34133541035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53014533143 - 214 = 53014516759 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53014533149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 185365358 + ... + 185365643.
It is an arithmetic number, because the mean of its divisors is an integer number (7785351042).
Almost surely, 253014533143 is an apocalyptic number.
53014533143 is a deficient number, since it is larger than the sum of its proper divisors (9268275193).
53014533143 is a wasteful number, since it uses less digits than its factorization.
53014533143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 370731025.
The product of its (nonzero) digits is 32400, while the sum is 32.
The spelling of 53014533143 in words is "fifty-three billion, fourteen million, five hundred thirty-three thousand, one hundred forty-three".
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