Base | Representation |
---|---|
bin | 1111011011011110111… |
… | …11001110001110101010 |
3 | 1212200102011110012211002 |
4 | 13231233133032032222 |
5 | 32141222231330010 |
6 | 1043314225035002 |
7 | 53205434554244 |
oct | 7555737161652 |
9 | 1780364405732 |
10 | 530151433130 |
11 | 194921732480 |
12 | 868b6785a62 |
13 | 3acba9c4177 |
14 | 1b93380b094 |
15 | dbccbc11a5 |
hex | 7b6f7ce3aa |
530151433130 has 64 divisors (see below), whose sum is σ = 1094216387328. Its totient is φ = 183054389760.
The previous prime is 530151433111. The next prime is 530151433213. The reversal of 530151433130 is 31334151035.
It is a junction number, because it is equal to n+sod(n) for n = 530151433093 and 530151433102.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 418157 + ... + 1111376.
It is an arithmetic number, because the mean of its divisors is an integer number (17097131052).
Almost surely, 2530151433130 is an apocalyptic number.
530151433130 is an abundant number, since it is smaller than the sum of its proper divisors (564064954198).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530151433130 is a wasteful number, since it uses less digits than its factorization.
530151433130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1529711.
The product of its (nonzero) digits is 8100, while the sum is 29.
Adding to 530151433130 its reverse (31334151035), we get a palindrome (561485584165).
The spelling of 530151433130 in words is "five hundred thirty billion, one hundred fifty-one million, four hundred thirty-three thousand, one hundred thirty".
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