53030003000030 has 64 divisors (see below), whose sum is σ = 112595090618880. Its totient is φ = 17606781143424.

The previous prime is 53030002999991. The next prime is 53030003000041. The reversal of 53030003000030 is 3000030003035.

53030003000030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 53030002999972 and 53030003000008.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 95545637 + ... + 96099056.

It is an arithmetic number, because the mean of its divisors is an integer number (1759298290920).

Almost surely, 2^{53030003000030} is an apocalyptic number.

53030003000030 is an abundant number, since it is smaller than the sum of its proper divisors (59565087618850).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53030003000030 is a wasteful number, since it uses less digits than its factorization.

53030003000030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191644833.

The product of its (nonzero) digits is 405, while the sum is 17.

Adding to 53030003000030 its reverse (3000030003035), we get a palindrome (56030033003065).

The spelling of 53030003000030 in words is "fifty-three trillion, thirty billion, three million, thirty", and thus it is an aban number and an uban number.