Base | Representation |
---|---|
bin | 110001011000111010… |
… | …111110101001110100 |
3 | 12001212212001110211021 |
4 | 301120322332221310 |
5 | 1332102023313130 |
6 | 40210132150524 |
7 | 3555112000606 |
oct | 613072765164 |
9 | 161785043737 |
10 | 53031463540 |
11 | 20543973520 |
12 | a340168444 |
13 | 5001b1c433 |
14 | 27d11a7176 |
15 | 15a5aa137a |
hex | c58ebea74 |
53031463540 has 48 divisors (see below), whose sum is σ = 127884496320. Its totient is φ = 18269210880.
The previous prime is 53031463493. The next prime is 53031463547. The reversal of 53031463540 is 4536413035.
It is a super-2 number, since 2×530314635402 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53031463496 and 53031463505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53031463547) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6339297 + ... + 6347656.
It is an arithmetic number, because the mean of its divisors is an integer number (2664260340).
Almost surely, 253031463540 is an apocalyptic number.
It is an amenable number.
53031463540 is an abundant number, since it is smaller than the sum of its proper divisors (74853032780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53031463540 is a wasteful number, since it uses less digits than its factorization.
53031463540 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12686992 (or 12686990 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 53031463540 its reverse (4536413035), we get a palindrome (57567876575).
The spelling of 53031463540 in words is "fifty-three billion, thirty-one million, four hundred sixty-three thousand, five hundred forty".
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