Base | Representation |
---|---|
bin | 111100010010110100100110… |
… | …0100000011010101100100000 |
3 | 2120112211012100002022010211002 |
4 | 1320211221030200122230200 |
5 | 1024003243241403223130 |
6 | 5115544313434411132 |
7 | 216465461515410041 |
oct | 17045511440325440 |
9 | 2515735302263732 |
10 | 530352435211040 |
11 | 143a94228465282 |
12 | 4b595a31590aa8 |
13 | 199c1035068020 |
14 | 94d72a28628c8 |
15 | 414aa3d409b45 |
hex | 1e25a4c81ab20 |
530352435211040 has 96 divisors (see below), whose sum is σ = 1359639282488256. Its totient is φ = 194327609748480.
The previous prime is 530352435211037. The next prime is 530352435211139. The reversal of 530352435211040 is 40112534253035.
It is a junction number, because it is equal to n+sod(n) for n = 530352435210985 and 530352435211003.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 972922682 + ... + 973467641.
It is an arithmetic number, because the mean of its divisors is an integer number (14162909192586).
Almost surely, 2530352435211040 is an apocalyptic number.
It is an amenable number.
530352435211040 is an abundant number, since it is smaller than the sum of its proper divisors (829286847277216).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530352435211040 is a wasteful number, since it uses less digits than its factorization.
530352435211040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1946390482 (or 1946390474 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 38.
Adding to 530352435211040 its reverse (40112534253035), we get a palindrome (570464969464075).
The spelling of 530352435211040 in words is "five hundred thirty trillion, three hundred fifty-two billion, four hundred thirty-five million, two hundred eleven thousand, forty".
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