Base | Representation |
---|---|
bin | 100110100101101001111… |
… | …0110111000000101001101 |
3 | 200210000101002202002110101 |
4 | 1031023103312320011031 |
5 | 1143343124232140300 |
6 | 15140225310211101 |
7 | 1055111523241264 |
oct | 115132366700515 |
9 | 20700332662411 |
10 | 5303544021325 |
11 | 1765247378500 |
12 | 717a421b3a91 |
13 | 2c61782034c4 |
14 | 14499b4655db |
15 | 92e560d5b6a |
hex | 4d2d3db814d |
5303544021325 has 72 divisors (see below), whose sum is σ = 7725349670976. Its totient is φ = 3596302195200.
The previous prime is 5303544021313. The next prime is 5303544021343. The reversal of 5303544021325 is 5231204453035.
It is not a de Polignac number, because 5303544021325 - 27 = 5303544021197 is a prime.
It is a super-2 number, since 2×53035440213252 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 5020552 + ... + 5984398.
It is an arithmetic number, because the mean of its divisors is an integer number (107296523208).
Almost surely, 25303544021325 is an apocalyptic number.
5303544021325 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
5303544021325 is a deficient number, since it is larger than the sum of its proper divisors (2421805649651).
5303544021325 is a wasteful number, since it uses less digits than its factorization.
5303544021325 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 964003 (or 963987 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 37.
The spelling of 5303544021325 in words is "five trillion, three hundred three billion, five hundred forty-four million, twenty-one thousand, three hundred twenty-five".
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