Base | Representation |
---|---|
bin | 11000001000000011001010… |
… | …01010001001111100110000 |
3 | 20221211211102001220211020201 |
4 | 30010001211022021330300 |
5 | 23423210304044414300 |
6 | 304500134541444544 |
7 | 14113651045426306 |
oct | 1404014512117460 |
9 | 227754361824221 |
10 | 53053133201200 |
11 | 159a47866662a0 |
12 | 5b4a076b70754 |
13 | 237ab731739b2 |
14 | d15adcdcc276 |
15 | 620078d4e66a |
hex | 304065289f30 |
53053133201200 has 60 divisors (see below), whose sum is σ = 139047439119768. Its totient is φ = 19292048435200.
The previous prime is 53053133201149. The next prime is 53053133201227. The reversal of 53053133201200 is 210233135035.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6028760737 + ... + 6028769536.
Almost surely, 253053133201200 is an apocalyptic number.
53053133201200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53053133201200 is an abundant number, since it is smaller than the sum of its proper divisors (85994305918568).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53053133201200 is a wasteful number, since it uses less digits than its factorization.
53053133201200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12057530302 (or 12057530291 counting only the distinct ones).
The product of its (nonzero) digits is 8100, while the sum is 28.
Adding to 53053133201200 its reverse (210233135035), we get a palindrome (53263366336235).
The spelling of 53053133201200 in words is "fifty-three trillion, fifty-three billion, one hundred thirty-three million, two hundred one thousand, two hundred".
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