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530550400003 = 13172400680543
BaseRepresentation
bin1111011100001110100…
…01001010010000000011
31212201102222011211110221
413232013101022100003
532143031400300003
61043422000203511
753221350664051
oct7560721122003
91781388154427
10530550400003
11195006962168
12869a8309597
133b052563440
141b9707c31d1
15dc02c2d7bd
hex7b8744a403

530550400003 has 8 divisors (see below), whose sum is σ = 604971497088. Its totient is φ = 460930664064.

The previous prime is 530550399941. The next prime is 530550400007. The reversal of 530550400003 is 300004055035.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-530550400003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530550400007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1200340051 + ... + 1200340492.

It is an arithmetic number, because the mean of its divisors is an integer number (75621437136).

Almost surely, 2530550400003 is an apocalyptic number.

530550400003 is a deficient number, since it is larger than the sum of its proper divisors (74421097085).

530550400003 is a wasteful number, since it uses less digits than its factorization.

530550400003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2400680573.

The product of its (nonzero) digits is 4500, while the sum is 25.

Adding to 530550400003 its reverse (300004055035), we get a palindrome (830554455038).

The spelling of 530550400003 in words is "five hundred thirty billion, five hundred fifty million, four hundred thousand, three".

Divisors: 1 13 17 221 2400680543 31208847059 40811569231 530550400003