Base | Representation |
---|---|
bin | 1111011100001110100… |
… | …01001010010000000011 |
3 | 1212201102222011211110221 |
4 | 13232013101022100003 |
5 | 32143031400300003 |
6 | 1043422000203511 |
7 | 53221350664051 |
oct | 7560721122003 |
9 | 1781388154427 |
10 | 530550400003 |
11 | 195006962168 |
12 | 869a8309597 |
13 | 3b052563440 |
14 | 1b9707c31d1 |
15 | dc02c2d7bd |
hex | 7b8744a403 |
530550400003 has 8 divisors (see below), whose sum is σ = 604971497088. Its totient is φ = 460930664064.
The previous prime is 530550399941. The next prime is 530550400007. The reversal of 530550400003 is 300004055035.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-530550400003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530550400007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1200340051 + ... + 1200340492.
It is an arithmetic number, because the mean of its divisors is an integer number (75621437136).
Almost surely, 2530550400003 is an apocalyptic number.
530550400003 is a deficient number, since it is larger than the sum of its proper divisors (74421097085).
530550400003 is a wasteful number, since it uses less digits than its factorization.
530550400003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2400680573.
The product of its (nonzero) digits is 4500, while the sum is 25.
Adding to 530550400003 its reverse (300004055035), we get a palindrome (830554455038).
The spelling of 530550400003 in words is "five hundred thirty billion, five hundred fifty million, four hundred thousand, three".
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