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53055064445 = 510611012889
BaseRepresentation
bin110001011010010101…
…000000100101111101
312001221111110112011212
4301122111000211331
51332124044030240
640212334054205
73555516415115
oct613225004575
9161844415155
1053055064445
11205562231a9
12a34804a365
135006993876
1427d438c045
1515a7bb4165
hexc5a54097d

53055064445 has 4 divisors (see below), whose sum is σ = 63666077340. Its totient is φ = 42444051552.

The previous prime is 53055064441. The next prime is 53055064463. The reversal of 53055064445 is 54446055035.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 15280420996 + 37774643449 = 123614^2 + 194357^2 .

It is a cyclic number.

It is not a de Polignac number, because 53055064445 - 22 = 53055064441 is a prime.

It is a super-3 number, since 3×530550644453 (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53055064441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5305506440 + ... + 5305506449.

It is an arithmetic number, because the mean of its divisors is an integer number (15916519335).

Almost surely, 253055064445 is an apocalyptic number.

It is an amenable number.

53055064445 is a deficient number, since it is larger than the sum of its proper divisors (10611012895).

53055064445 is a wasteful number, since it uses less digits than its factorization.

53055064445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10611012894.

The product of its (nonzero) digits is 720000, while the sum is 41.

The spelling of 53055064445 in words is "fifty-three billion, fifty-five million, sixty-four thousand, four hundred forty-five".

Divisors: 1 5 10611012889 53055064445