Base | Representation |
---|---|
bin | 111100010100010001100010… |
… | …1100110110111111001111100 |
3 | 2120120112021112120100110200212 |
4 | 1320220203011212313321330 |
5 | 1024020031032033123200 |
6 | 5120220123524211552 |
7 | 216516056013364364 |
oct | 17050430546677174 |
9 | 2516467476313625 |
10 | 530552035442300 |
11 | 1440609445a9293 |
12 | 4b608657239bb8 |
13 | 19a06ac45c6c41 |
14 | 9502bd97dd9a4 |
15 | 4150d21714035 |
hex | 1e288c59b7e7c |
530552035442300 has 36 divisors (see below), whose sum is σ = 1165168976167896. Its totient is φ = 209663936894400.
The previous prime is 530552035442267. The next prime is 530552035442327. The reversal of 530552035442300 is 3244530255035.
It is a happy number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 31960957691 + ... + 31960974290.
Almost surely, 2530552035442300 is an apocalyptic number.
530552035442300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
530552035442300 is an abundant number, since it is smaller than the sum of its proper divisors (634616940725596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530552035442300 is a wasteful number, since it uses less digits than its factorization.
530552035442300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63921932078 (or 63921932071 counting only the distinct ones).
The product of its (nonzero) digits is 1080000, while the sum is 41.
Adding to 530552035442300 its reverse (3244530255035), we get a palindrome (533796565697335).
The spelling of 530552035442300 in words is "five hundred thirty trillion, five hundred fifty-two billion, thirty-five million, four hundred forty-two thousand, three hundred".
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