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530591040 = 26335731283
BaseRepresentation
bin11111101000000…
…010110101000000
31100222101211002000
4133220002311000
52041312403130
6124352224000
716101643440
oct3750026500
91328354060
10530591040
112525609a1
1212983b000
1385c060c5
145067a120
15318ac260
hex1fa02d40

530591040 has 448 divisors, whose sum is σ = 2216017920. Its totient is φ = 116951040.

The previous prime is 530591021. The next prime is 530591041. The reversal of 530591040 is 40195035.

530591040 is a `hidden beast` number, since 5 + 30 + 591 + 0 + 40 = 666.

It is a tau number, because it is divible by the number of its divisors (448).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 530590995 and 530591013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530591041) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1874739 + ... + 1875021.

Almost surely, 2530591040 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 530591040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1108008960).

530591040 is an abundant number, since it is smaller than the sum of its proper divisors (1685426880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

530591040 is a wasteful number, since it uses less digits than its factorization.

530591040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 347 (or 331 counting only the distinct ones).

The product of its (nonzero) digits is 2700, while the sum is 27.

The square root of 530591040 is about 23034.5618582164. The cubic root of 530591040 is about 809.5679451655.

The spelling of 530591040 in words is "five hundred thirty million, five hundred ninety-one thousand, forty".