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530712000000 = 293656713
BaseRepresentation
bin1111011100100001110…
…01100111011000000000
31212201212020020222000000
413232100321213120000
532143344233000000
61043450012000000
753225352366060
oct7562071473000
91781766228000
10530712000000
1119508a0a7686
1286a32460000
133b079b94240
141b98804b3a0
15dc12000000
hex7b90e67600

530712000000 has 1960 divisors, whose sum is σ = 2445897754608. Its totient is φ = 111974400000.

The previous prime is 530711999953. The next prime is 530712000011. The reversal of 530712000000 is 217035.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 195 ways as a sum of consecutive naturals, for example, 40823999994 + ... + 40824000006.

Almost surely, 2530712000000 is an apocalyptic number.

530712000000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 530712000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1222948877304).

530712000000 is an abundant number, since it is smaller than the sum of its proper divisors (1915185754608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

530712000000 is an frugal number, since it uses more digits than its factorization.

530712000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86 (or 30 counting only the distinct ones).

The product of its (nonzero) digits is 210, while the sum is 18.

Adding to 530712000000 its reverse (217035), we get a palindrome (530712217035).

The spelling of 530712000000 in words is "five hundred thirty billion, seven hundred twelve million", and thus it is an aban number.