Base | Representation |
---|---|
bin | 11000001001011110101001… |
… | …11001100001100101010000 |
3 | 20222000112012021121021002201 |
4 | 30010233110321201211100 |
5 | 23430011403121430000 |
6 | 304534501003252544 |
7 | 14120340215015452 |
oct | 1404572471414520 |
9 | 228015167537081 |
10 | 53102252530000 |
11 | 15a135a21a9003 |
12 | 5b576a4b1a154 |
13 | 23826a0626aab |
14 | d1823c7942d2 |
15 | 6214a123496a |
hex | 304bd4e61950 |
53102252530000 has 100 divisors (see below), whose sum is σ = 130673502209668. Its totient is φ = 20892689280000.
The previous prime is 53102252529983. The next prime is 53102252530013. The reversal of 53102252530000 is 3525220135.
It can be written as a sum of positive squares in 10 ways, for example, as 51700529134864 + 1401723395136 = 7190308^2 + 1183944^2 .
It is a tau number, because it is divible by the number of its divisors (100).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 42916437 + ... + 44136436.
Almost surely, 253102252530000 is an apocalyptic number.
53102252530000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53102252530000 is an abundant number, since it is smaller than the sum of its proper divisors (77571249679668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53102252530000 is an equidigital number, since it uses as much as digits as its factorization.
53102252530000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87052962 (or 87052941 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 28.
Adding to 53102252530000 its reverse (3525220135), we get a palindrome (53105777750135).
The spelling of 53102252530000 in words is "fifty-three trillion, one hundred two billion, two hundred fifty-two million, five hundred thirty thousand".
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