Base | Representation |
---|---|
bin | 1111011101100001001… |
… | …00100011100010000001 |
3 | 1212210020021002100101000 |
4 | 13232300210203202001 |
5 | 32200441244201040 |
6 | 1044014432402213 |
7 | 53244463653624 |
oct | 7566044434201 |
9 | 1783207070330 |
10 | 531243350145 |
11 | 195332026932 |
12 | 86b603a6369 |
13 | 3b132ca4a01 |
14 | 1b9d8843dbb |
15 | dc439ac130 |
hex | 7bb0923881 |
531243350145 has 64 divisors (see below), whose sum is σ = 967865184000. Its totient is φ = 276320056320.
The previous prime is 531243350129. The next prime is 531243350147. The reversal of 531243350145 is 541053342135.
531243350145 is a `hidden beast` number, since 5 + 31 + 2 + 433 + 50 + 145 = 666.
It is not a de Polignac number, because 531243350145 - 24 = 531243350129 is a prime.
It is not an unprimeable number, because it can be changed into a prime (531243350147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3767881 + ... + 3906329.
It is an arithmetic number, because the mean of its divisors is an integer number (15122893500).
Almost surely, 2531243350145 is an apocalyptic number.
It is an amenable number.
531243350145 is a deficient number, since it is larger than the sum of its proper divisors (436621833855).
531243350145 is a wasteful number, since it uses less digits than its factorization.
531243350145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 139167 (or 139161 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 36.
The spelling of 531243350145 in words is "five hundred thirty-one billion, two hundred forty-three million, three hundred fifty thousand, one hundred forty-five".
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