Base | Representation |
---|---|
bin | 100110101001111010111… |
… | …1010100010101001110001 |
3 | 200210220000120101101220221 |
4 | 1031103311322202221301 |
5 | 1144020410031421230 |
6 | 15144342333133041 |
7 | 1055554535212222 |
oct | 115236572425161 |
9 | 20726016341827 |
10 | 5312705342065 |
11 | 1769118733360 |
12 | 71977a32a181 |
13 | 2c6ca8217454 |
14 | 1451ca071249 |
15 | 932e052b27a |
hex | 4d4f5ea2a71 |
5312705342065 has 128 divisors (see below), whose sum is σ = 7865440174080. Its totient is φ = 3394811289600.
The previous prime is 5312705342047. The next prime is 5312705342081. The reversal of 5312705342065 is 5602435072135.
It is a happy number.
It is not a de Polignac number, because 5312705342065 - 25 = 5312705342033 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 363055989 + ... + 363070621.
It is an arithmetic number, because the mean of its divisors is an integer number (61448751360).
Almost surely, 25312705342065 is an apocalyptic number.
5312705342065 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
5312705342065 is a deficient number, since it is larger than the sum of its proper divisors (2552734832015).
5312705342065 is a wasteful number, since it uses less digits than its factorization.
5312705342065 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14983.
The product of its (nonzero) digits is 756000, while the sum is 43.
The spelling of 5312705342065 in words is "five trillion, three hundred twelve billion, seven hundred five million, three hundred forty-two thousand, sixty-five".
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