Base | Representation |
---|---|
bin | 11000001010010100111111… |
… | …00011110011000101001111 |
3 | 20222010022111011212212012202 |
4 | 30011022133203303011033 |
5 | 23431001123114210020 |
6 | 305000123303152115 |
7 | 14122422114644513 |
oct | 1405123743630517 |
9 | 228108434785182 |
10 | 53131422413135 |
11 | 15a24a00900a40 |
12 | 5b61285a4563b |
13 | 238536ba22a81 |
14 | d19808874143 |
15 | 62210c037e75 |
hex | 30529f8f314f |
53131422413135 has 8 divisors (see below), whose sum is σ = 69553862068176. Its totient is φ = 38641034482240.
The previous prime is 53131422413053. The next prime is 53131422413149.
It is a happy number.
53131422413135 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53131422413135 - 28 = 53131422412879 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 483012930974 + ... + 483012931083.
It is an arithmetic number, because the mean of its divisors is an integer number (8694232758522).
Almost surely, 253131422413135 is an apocalyptic number.
53131422413135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53131422413135 is a deficient number, since it is larger than the sum of its proper divisors (16422439655041).
53131422413135 is a wasteful number, since it uses less digits than its factorization.
53131422413135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 966025862073.
The product of its digits is 129600, while the sum is 38.
It can be divided in two parts, 5313142 and 2413135, that added together give a palindrome (7726277).
The spelling of 53131422413135 in words is "fifty-three trillion, one hundred thirty-one billion, four hundred twenty-two million, four hundred thirteen thousand, one hundred thirty-five".
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