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53141421300 = 2235211210391409
BaseRepresentation
bin110001011111011110…
…011011110011110100
312002011111221220111220
4301133132123303310
51332313200440200
640225101030340
73560615425302
oct613736336364
9162144856456
1053141421300
112059aa46400
12a370b553b0
13501b83b4b6
142801a2b272
1515b05714a0
hexc5f79bcf4

53141421300 has 216 divisors, whose sum is σ = 169287081600. Its totient is φ = 12861235200.

The previous prime is 53141421299. The next prime is 53141421313. The reversal of 53141421300 is 312414135.

It is a happy number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 37714996 + ... + 37716404.

Almost surely, 253141421300 is an apocalyptic number.

53141421300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53141421300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (84643540800).

53141421300 is an abundant number, since it is smaller than the sum of its proper divisors (116145660300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53141421300 is a wasteful number, since it uses less digits than its factorization.

53141421300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2487 (or 2469 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 53141421300 its reverse (312414135), we get a palindrome (53453835435).

The spelling of 53141421300 in words is "fifty-three billion, one hundred forty-one million, four hundred twenty-one thousand, three hundred".