Base | Representation |
---|---|
bin | 110001011111100000… |
… | …101100000010000000 |
3 | 12002011120001220211212 |
4 | 301133200230002000 |
5 | 1332313323341112 |
6 | 40225121425252 |
7 | 3560623435454 |
oct | 613740540200 |
9 | 162146056755 |
10 | 53142012032 |
11 | 205a030a20a |
12 | a37119b228 |
13 | 501b9b7345 |
14 | 2801b42664 |
15 | 15b063b522 |
hex | c5f82c080 |
53142012032 has 16 divisors (see below), whose sum is σ = 105868852350. Its totient is φ = 26571005952.
The previous prime is 53142012023. The next prime is 53142012041. The reversal of 53142012032 is 23021024135.
It is an interprime number because it is at equal distance from previous prime (53142012023) and next prime (53142012041).
It can be written as a sum of positive squares in only one way, i.e., 50596204096 + 2545807936 = 224936^2 + 50456^2 .
It is a tau number, because it is divible by the number of its divisors (16).
It is a junction number, because it is equal to n+sod(n) for n = 53142011989 and 53142012007.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207585857 + ... + 207586112.
Almost surely, 253142012032 is an apocalyptic number.
It is an amenable number.
53142012032 is a deficient number, since it is larger than the sum of its proper divisors (52726840318).
53142012032 is an equidigital number, since it uses as much as digits as its factorization.
53142012032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 415171983 (or 415171971 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 53142012032 its reverse (23021024135), we get a palindrome (76163036167).
The spelling of 53142012032 in words is "fifty-three billion, one hundred forty-two million, twelve thousand, thirty-two".
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