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53142012032 = 27415171969
BaseRepresentation
bin110001011111100000…
…101100000010000000
312002011120001220211212
4301133200230002000
51332313323341112
640225121425252
73560623435454
oct613740540200
9162146056755
1053142012032
11205a030a20a
12a37119b228
13501b9b7345
142801b42664
1515b063b522
hexc5f82c080

53142012032 has 16 divisors (see below), whose sum is σ = 105868852350. Its totient is φ = 26571005952.

The previous prime is 53142012023. The next prime is 53142012041. The reversal of 53142012032 is 23021024135.

It is an interprime number because it is at equal distance from previous prime (53142012023) and next prime (53142012041).

It can be written as a sum of positive squares in only one way, i.e., 50596204096 + 2545807936 = 224936^2 + 50456^2 .

It is a tau number, because it is divible by the number of its divisors (16).

It is a junction number, because it is equal to n+sod(n) for n = 53142011989 and 53142012007.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207585857 + ... + 207586112.

Almost surely, 253142012032 is an apocalyptic number.

It is an amenable number.

53142012032 is a deficient number, since it is larger than the sum of its proper divisors (52726840318).

53142012032 is an equidigital number, since it uses as much as digits as its factorization.

53142012032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 415171983 (or 415171971 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 53142012032 its reverse (23021024135), we get a palindrome (76163036167).

The spelling of 53142012032 in words is "fifty-three billion, one hundred forty-two million, twelve thousand, thirty-two".

Divisors: 1 2 4 8 16 32 64 128 415171969 830343938 1660687876 3321375752 6642751504 13285503008 26571006016 53142012032