Base | Representation |
---|---|
bin | 100110101010101111101… |
… | …0100011000000010011111 |
3 | 200211001120210220102011122 |
4 | 1031111133110120002133 |
5 | 1144033020233101030 |
6 | 15145234023441155 |
7 | 1055646420203003 |
oct | 115253724300237 |
9 | 20731523812148 |
10 | 5314473722015 |
11 | 1769945960397 |
12 | 719b925b61bb |
13 | 2c71ca6b6013 |
14 | 145316c76703 |
15 | 933958da8e5 |
hex | 4d55f51809f |
5314473722015 has 8 divisors (see below), whose sum is σ = 6752507788080. Its totient is φ = 4001486096512.
The previous prime is 5314473721967. The next prime is 5314473722017. The reversal of 5314473722015 is 5102273744135.
It is a happy number.
5314473722015 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5314473722015 - 26 = 5314473721951 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5314473722017) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31261610045 + ... + 31261610214.
It is an arithmetic number, because the mean of its divisors is an integer number (844063473510).
Almost surely, 25314473722015 is an apocalyptic number.
5314473722015 is a deficient number, since it is larger than the sum of its proper divisors (1438034066065).
5314473722015 is a wasteful number, since it uses less digits than its factorization.
5314473722015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62523220281.
The product of its (nonzero) digits is 705600, while the sum is 44.
The spelling of 5314473722015 in words is "five trillion, three hundred fourteen billion, four hundred seventy-three million, seven hundred twenty-two thousand, fifteen".
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