Base | Representation |
---|---|
bin | 11000001101110100010001… |
… | …10100111010111111111111 |
3 | 20222112202220122220211210212 |
4 | 30012322020310322333333 |
5 | 23434432130312012320 |
6 | 305131150510223035 |
7 | 14134164600365135 |
oct | 1406721064727777 |
9 | 228482818824725 |
10 | 53251300110335 |
11 | 15a70827721168 |
12 | 5b805607b4a7b |
13 | 2393764788002 |
14 | d2153b861755 |
15 | 6252c63d09c5 |
hex | 306e88d3afff |
53251300110335 has 12 divisors (see below), whose sum is σ = 67881588100968. Its totient is φ = 40095096552576.
The previous prime is 53251300110329. The next prime is 53251300110341. The reversal of 53251300110335 is 53301100315235.
It is an interprime number because it is at equal distance from previous prime (53251300110329) and next prime (53251300110341).
It is not a de Polignac number, because 53251300110335 - 220 = 53251299061759 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18426053957 + ... + 18426056846.
It is an arithmetic number, because the mean of its divisors is an integer number (5656799008414).
Almost surely, 253251300110335 is an apocalyptic number.
53251300110335 is a deficient number, since it is larger than the sum of its proper divisors (14630287990633).
53251300110335 is a wasteful number, since it uses less digits than its factorization.
53251300110335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36852110842 (or 36852110825 counting only the distinct ones).
The product of its (nonzero) digits is 20250, while the sum is 32.
The spelling of 53251300110335 in words is "fifty-three trillion, two hundred fifty-one billion, three hundred million, one hundred ten thousand, three hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •