Base | Representation |
---|---|
bin | 11000001111011001000101… |
… | …01000010111111111000000 |
3 | 20222201221121101021012012021 |
4 | 30013230202220113333000 |
5 | 23441324000022320000 |
6 | 305212101050011224 |
7 | 14141122001025646 |
oct | 1407544250277700 |
9 | 228657541235167 |
10 | 53305420120000 |
11 | 15a91779a96484 |
12 | 5b8ab45416b14 |
13 | 23988aac77879 |
14 | d23dd3425196 |
15 | 6268e280411a |
hex | 307b22a17fc0 |
53305420120000 has 70 divisors (see below), whose sum is σ = 132180117735248. Its totient is φ = 21322168032000.
The previous prime is 53305420119947. The next prime is 53305420120003. The reversal of 53305420120000 is 2102450335.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53305420120003) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 666277752 + ... + 666357751.
Almost surely, 253305420120000 is an apocalyptic number.
53305420120000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53305420120000 is an abundant number, since it is smaller than the sum of its proper divisors (78874697615248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53305420120000 is an equidigital number, since it uses as much as digits as its factorization.
53305420120000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1332635535 (or 1332635510 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 25.
Adding to 53305420120000 its reverse (2102450335), we get a palindrome (53307522570335).
The spelling of 53305420120000 in words is "fifty-three trillion, three hundred five billion, four hundred twenty million, one hundred twenty thousand".
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