Base | Representation |
---|---|
bin | 110001101011111110… |
… | …111000010101010100 |
3 | 12002201010210110221122 |
4 | 301223332320111110 |
5 | 1333230410101312 |
6 | 40301554303112 |
7 | 3566044112426 |
oct | 615376702524 |
9 | 162633713848 |
10 | 53351253332 |
11 | 20698434303 |
12 | a40b287a98 |
13 | 5053158a70 |
14 | 282184c816 |
15 | 15c3bbdb72 |
hex | c6bfb8554 |
53351253332 has 24 divisors (see below), whose sum is σ = 103790034432. Its totient is φ = 23829343200.
The previous prime is 53351253283. The next prime is 53351253349. The reversal of 53351253332 is 23335215335.
It is a happy number.
It is a super-2 number, since 2×533512533322 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53351253292 and 53351253301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16546544 + ... + 16549767.
It is an arithmetic number, because the mean of its divisors is an integer number (4324584768).
Almost surely, 253351253332 is an apocalyptic number.
53351253332 is a gapful number since it is divisible by the number (52) formed by its first and last digit.
It is an amenable number.
53351253332 is a deficient number, since it is larger than the sum of its proper divisors (50438781100).
53351253332 is a wasteful number, since it uses less digits than its factorization.
53351253332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33096359 (or 33096357 counting only the distinct ones).
The product of its digits is 121500, while the sum is 35.
Adding to 53351253332 its reverse (23335215335), we get a palindrome (76686468667).
The spelling of 53351253332 in words is "fifty-three billion, three hundred fifty-one million, two hundred fifty-three thousand, three hundred thirty-two".
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