Base | Representation |
---|---|
bin | 11000010000110010001011… |
… | …10100110110111100000111 |
3 | 20222220112002002110211100121 |
4 | 30020121011310312330013 |
5 | 23443114431320012320 |
6 | 305250051434322411 |
7 | 14144434254554416 |
oct | 1410310564667407 |
9 | 228815062424317 |
10 | 53353255235335 |
11 | 15aaaa96733650 |
12 | 5b98275289407 |
13 | 23a026235c343 |
14 | d2645041947d |
15 | 627c920b68aa |
hex | 308645d36f07 |
53353255235335 has 64 divisors (see below), whose sum is σ = 72161600661504. Its totient is φ = 37535505408000.
The previous prime is 53353255235311. The next prime is 53353255235341.
53353255235335 is nontrivially palindromic in base 10.
53353255235335 is digitally balanced in base 6, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53353255235335 - 27 = 53353255235207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 150468964 + ... + 150823126.
It is an arithmetic number, because the mean of its divisors is an integer number (1127525010336).
Almost surely, 253353255235335 is an apocalyptic number.
53353255235335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53353255235335 is a deficient number, since it is larger than the sum of its proper divisors (18808345426169).
53353255235335 is a wasteful number, since it uses less digits than its factorization.
53353255235335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 354904.
The product of its digits is 45562500, while the sum is 52.
The spelling of 53353255235335 in words is "fifty-three trillion, three hundred fifty-three billion, two hundred fifty-five million, two hundred thirty-five thousand, three hundred thirty-five".
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