Base | Representation |
---|---|
bin | 100110111100110110000… |
… | …0011101010010110100111 |
3 | 200221202220121201010202112 |
4 | 1031321230003222112213 |
5 | 1200202121042300210 |
6 | 15215142541031235 |
7 | 1061523544324124 |
oct | 115715403522647 |
9 | 20852817633675 |
10 | 5353342150055 |
11 | 178438109a699 |
12 | 72561b55551b |
13 | 2caa831b2273 |
14 | 14716304774b |
15 | 943bcda1d05 |
hex | 4de6c0ea5a7 |
5353342150055 has 8 divisors (see below), whose sum is σ = 6801893555472. Its totient is φ = 4030751736448.
The previous prime is 5353342150049. The next prime is 5353342150069. The reversal of 5353342150055 is 5500512433535.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5353342150055 - 222 = 5353337955751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5353342149994 and 5353342150021.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31490247857 + ... + 31490248026.
It is an arithmetic number, because the mean of its divisors is an integer number (850236694434).
Almost surely, 25353342150055 is an apocalyptic number.
5353342150055 is a deficient number, since it is larger than the sum of its proper divisors (1448551405417).
5353342150055 is a wasteful number, since it uses less digits than its factorization.
5353342150055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62980495905.
The product of its (nonzero) digits is 675000, while the sum is 41.
The spelling of 5353342150055 in words is "five trillion, three hundred fifty-three billion, three hundred forty-two million, one hundred fifty thousand, fifty-five".
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