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54140111311440 = 24357114368131621
BaseRepresentation
bin11000100111101011110100…
…00110100101001001010000
321002200202002110000001102010
430103311322012211021100
524044012421443431230
6311051342423022520
714255331300056550
oct1423657206451120
9232622073001363
1054140111311440
1116283768450820
1260a487189aa40
13242951018494b
14d52576c6d160
1563d4964c79b0
hex313d7a1a5250

54140111311440 has 320 divisors, whose sum is σ = 214114250668032. Its totient is φ = 10988267673600.

The previous prime is 54140111311367. The next prime is 54140111311441. The reversal of 54140111311440 is 4411311104145.

It is a super-2 number, since 2×541401113114402 (a number of 28 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 54140111311398 and 54140111311407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54140111311441) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 33271171 + ... + 34860450.

Almost surely, 254140111311440 is an apocalyptic number.

It is an amenable number.

54140111311440 is an abundant number, since it is smaller than the sum of its proper divisors (159974139356592).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

54140111311440 is a wasteful number, since it uses less digits than its factorization.

54140111311440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68131698 (or 68131692 counting only the distinct ones).

The product of its (nonzero) digits is 3840, while the sum is 30.

Adding to 54140111311440 its reverse (4411311104145), we get a palindrome (58551422415585).

The spelling of 54140111311440 in words is "fifty-four trillion, one hundred forty billion, one hundred eleven million, three hundred eleven thousand, four hundred forty".